MADRID 3 Nov. () –
The candidate of the liberal and pro-European Action and Solidarity Party (PAS), Maia Sandu, has won the second round of the presidential elections held this Sunday in Moldova with 50.66 percent of the votes, according to official data corresponding to 93, 51 percent of the votes.
Sandu thus prevails over the candidate of the Party of Socialists (PSRM), Alexandr Stoianoglo, considered close to Russia, who has achieved 49.34 percent support. The result includes 728,789 votes for Sandu compared to 709,775 votes for Stoianoglo.
Sandu was the candidate with the most votes in the first round with almost 42.5 percent of the votes; while Stoianoglo managed to convince about 30 percent of the electorate, and now aims to convince the rest of the voters to unseat the current Moldovan president.
The few polls that have been carried out in the two weeks that have elapsed since the first round of the presidential elections were held show that Sandu would win more than half of the votes, which would guarantee another four years to move forward. with its policies, focused on European integration.
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